问题描述

例如我有一个这样的字符串:

$html = '<a href="test.html">test</a><a href="http://mydomain.com/test.html">test</a><a href="http://otherdomain.com/test.html">test</a><a href="someothertest/otherdir/hi.html">hi</a>';

并且我想将绝对 url 附加到所有没有给出绝对域的 href 中.

$html = '<a href="http://mydomain.com/test.html">test</a><a href="http://mydomain.com/test.html">test</a><a href="http://otherdomain.com/test.html">test</a><a href="http://mydomain.com/someothertest/otherdir/hi.html">hi</a>';

最好的方法是什么?我猜正则表达式有什么问题，但我的正则表达式技能是 ** ;)

提前致谢！

找到了一个好方法:

$html = preg_replace("#(<s*as+[^>]*hrefs*=s*["'])(?!http)([^"'>]+)(["'>]+)#", '$1http://mydomain.com/$2$3', $html);

如果您的 $html 中还有 mailto 链接，您可以使用 (?!http|mailto)

for example i've got a string like this:

$html = '
            <a href="test.html">test</a>
            <a href="http://mydomain.com/test.html">test</a>
            <a href="http://otherdomain.com/test.html">test</a>
            <a href="someothertest/otherdir/hi.html">hi</a>
        ';

and i want to append the absolute url to all hrefs where no abolute domain is given.

$html = '
            <a href="http://mydomain.com/test.html">test</a>
            <a href="http://mydomain.com/test.html">test</a>
            <a href="http://otherdomain.com/test.html">test</a>
            <a href="http://mydomain.com/someothertest/otherdir/hi.html">hi</a>
        ';  

whats the best way to do that? i guess something with RegEx, but my RegEx skills are ** ;)

thanks in advance!

found a good way :

$html = preg_replace("#(<s*as+[^>]*hrefs*=s*["'])(?!http)([^"'>]+)(["'>]+)#", '$1http://mydomain.com/$2$3', $html);

you can use (?!http|mailto) if you have also mailto links in your $html

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