问题描述

我想选择不属于特定服务的成员.我有 3 张桌子:

I'd like to select members who are not in specific service. I have 3 tables :

• 成员
• 服务
• membre_service(membre 和 service 之间的关系)

• membre
• service
• membre_service (relation between membre and service)

我使用的是学说 2，在 SQL 中我的查询是:

I'm using doctrine 2 and in SQL my query is :

SELECT m.* FROM membre m WHERE m.`id` NOT IN (
    SELECT ms.membre_id FROM membre_service ms WHERE ms.service_id != 29
)

在 Doctrine 中，我这样做:

In Doctrine, I do :

$qb  = $this->_em->createQueryBuilder();
$qb2 = $qb;
$qb2->select('m.id')
        ->from('CustomEntityMembreService', 'ms')
        ->leftJoin('ms.membre', 'm')
        ->where('ms.id != ?1')
        ->setParameter(1, $service);

    $qb  = $this->_em->createQueryBuilder();
    $qb->select('m')
        ->from('CustomEntityMembre', 'm')
        ->where($qb->expr()->notIn('m.id', $qb2->getDQL())
    );
    $query  = $qb->getQuery();
    //$query->useResultCache(true, 1200, __FUNCTION__);

    return $query->getResult();

我收到以下错误:

语义错误] line 0, col 123 near 'm WHERE ms.id': Error: 'm' is already defined.

Semantical Error] line 0, col 123 near 'm WHERE ms.id': Error: 'm' is already defined.

推荐答案

同一个查询中不能定义2次相同的别名

The same alias cannot be defined 2 times in the same query

$qb  = $this->_em->createQueryBuilder();
$qb2 = $qb;
$qb2->select('m.id')
    ->from('CustomEntityMembreService', 'ms')
    ->leftJoin('ms.membre', 'm')
    ->where('ms.id != ?1');

$qb  = $this->_em->createQueryBuilder();
$qb->select('mm')
    ->from('CustomEntityMembre', 'mm')
    ->where($qb->expr()->notIn('mm.id', $qb2->getDQL())
);
$qb->setParameter(1, $service);
$query  = $qb->getQuery();

return $query->getResult();

理想情况下，您应该为实体使用多对多关系，在这种情况下，您的查询会简单得多.

Ideally you should use many-to-many relation for your entity, in this case your query is going to be much simpler.

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