问题描述
我有一个脚本可以动态调用和显示目录中的图像，对它进行分页的最佳方法是什么?我希望能够通过脚本中的变量控制每页显示的图像数量.我正在考虑使用 URL 变量(即 - http://domain.com/page.php?page=1) 但我不确定如何去做.
I've got a script that dynamically calls and displays images from a directory, what would be the best way to paginate this? I'd like to be able to control the number of images that are displayed per page through a variable within the script. I'm thinking of using URL varriables (ie - http://domain.com/page.php?page=1) but am unsure how to go about this.
感谢您的帮助.
推荐答案
分页是同一个概念，不管有没有 sql.你只需要你的基本变量，然后你就可以创建你想要的内容.这是一些准代码:
pagination is the same concept with or without sql. you just need your basic variables, then you can create the content you want. here's some quasi-code:
$itemsPerPage = 5;
$currentPage = isset($_GET['page']) ? $_GET['page'] : 1;
$totalItems = getTotalItems();
$totalPages = ceil($totalItems / $itemsPerPage);
function getTotalItems() {
// since they're images, perhaps we'll scan a directory of images to determine
// how many images we have in total
}
function getItemsFromPage($page, $itemsPerPage) {
// function to grab $itemsPerPage based on which $page we're on
}
function getPager($totalPages, $currentPage) {
// build your pager
}
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