如何查看用户在测验中的选择是否正确?

本文介绍了如何查看用户在测验中的选择是否正确?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！

问题描述

我正在尝试检查用户选择的答案是否正确，但无法正常工作:

I am trying to check if the answer that the user chose was correct, but it doesn't work properly:

                        <form method="post">
                        <?php
                            $question = mysql_query("SELECT * FROM `questions`");
                            $stat = mysql_fetch_assoc($question);
                            $num = mysql_num_rows($question);
                            $questionid = 0;
                            for($i=0;$i<=$num;$i++)
                            {
                                $question = mysql_query("SELECT * FROM `questions` WHERE `id`='$i'");
                                $stat = mysql_fetch_assoc($question);
                                //if($stat['answer'] == null
                                echo $stat['question'] . '<br />';
                                echo '<input type="radio" name="a'.$x.'" value="'.$x.'" />' .$stat['answer1']."<br />";
                                echo '<input type="radio" name="a'.$x.'" value="'.$x.'" />' .$stat['answer2'] . '<br />';
                                echo '<input type="radio" name="a'.$x.'" value="'.$x.'" />' .$stat['answer3'] . '<br />';
                                echo '<input type="radio" name="a'.$x.'" value="'.$x.'" />' .$stat['answer4'] . '<br />';
                                $questionid++;
                                $x = $x+1;
                            }
                            echo $result;
                        ?>
                        <input type="submit" name="go" value="Go" />
                    </form>

那部分基本上:

$x = 1;
$question = mysql_query("SELECT * FROM `questions`");
$stat = mysql_fetch_assoc($question);
$num = mysql_num_rows($question);
if(isset($_POST['go']))
{
    for($i=0;$i<$num;$i++)
    {
        if ($_POST['ans'.$x] == $row['correct']) 
        { 
            $result = $result + 1; 
        }
        $x = $x + 1;
    }
}

由于某种原因它没有正确发布结果，我认为代码有问题，希望得到帮助.

For some reason it doesn't post the results properly and I think something is wrong with the code, would appreciate help.

推荐答案

这是帮助您的另一种尝试.

Here's another attempt at helping you.

我实际上写了一个完整的解决方案"，在这个过程中发现了你的代码中的一些小错误 - 还有一些我无法理解的东西.

I actually wrote a "complete solution", and in the process discovered a few little bugs in your code - plus some things I just couldn't understand.

主要错误:您所有的单选按钮都具有相同的值 ($x)，因此无论您为问题 1 按下哪个按钮，答案都是1"，等等.您还做了其他一些我无法完成的事情弄清楚 - 所以我所做的是创建一个简单的流程 - 一个页面提出问题，另一个页面评估结果.

Principal bug: all your radio buttons have the same value ($x), so no matter what button you press for question 1, the answer is "1", etc. There were other things you did that I could not quite figure out - so what I did instead was create a simple flow - one page that asks the questions, and another that evaluates the results.

问题页面(我混淆了数据库的访问参数 - 不，我不使用密码"作为我的密码！):

Question page (I obfuscated access parameters for my database - no, I don't use "password" as my password!):

<html>
<body>
<form action="./evaluate.php" method="post">
<?php
$server = mysql_connect ('localhost', 'username, 'password');
mysql_select_db("questionnaire", $server);

$question = mysql_query("SELECT * FROM `Questions`;");
$x = 0;
while ($row = mysql_fetch_assoc($question))
{
   echo $row['question'] . '<br />';
   echo '<input type="radio" name="a'.$x.'" value=1 />' .$row['answer1'] . '<br />';
   echo '<input type="radio" name="a'.$x.'" value=2 />' .$row['answer2'] . '<br />';
   echo '<input type="radio" name="a'.$x.'" value=3 />' .$row['answer3'] . '<br />';
   echo '<input type="radio" name="a'.$x.'" value=4 />' .$row['answer4'] . '<br />';
   $x = $x + 1;

}
mysql_close($server);
?>

<input type="submit" name="Submit" value="Submit" />
<br>
</form>
</body>
</html>

和评估.php:我稍微更改了代码以使输出更清晰"，并添加红色/绿色触摸以显示已正确和错误回答的问题.显然，如果您愿意，您可以更进一步...

and evaluate.php: I changed the code a bit to make the output "cleaner", and add a red/green touch to show questions that had been answered correctly and incorrectly. Obviously you can take these things much further if you want...

<html>
<body>

<?php
$server = mysql_connect ('localhost', 'username', 'password');
mysql_select_db("questionnaire", $server);

$question = mysql_query("SELECT * FROM `Questions`;");
$x = 0;
$score = 0;
while ($row = mysql_fetch_assoc($question))
{
    echo $row['question'] . '?<br />';

    $answered = $row['answer'.$_POST['a'.$x]] ;
    $correct = $row['correct'] ;

    if ($answered == $correct ) {
        $score++;
        $acolor = 'green' ;
    }
    else {
        $acolor = 'red' ;
    }

    echo 'you answered <font color=' . $acolor . '>' . $answered . '<font color=black> <br />';


    echo 'the correct answer was ' . $correct . '<br />' ;
    echo '-------------------------------------- <br />' ;

    $x = $x + 1;
}
echo 'You had a total of ' . $score . ' out of ' . $x . ' questions right!';
mysql_close($server);
?>

</body>
</html>

这产生了(对于我做的一个简单的三问题多项选择)预期的结果.让我知道它是否适合您！

This produced (for a simple three-question multiple choice I made) the expected results. Let me know if it works for you!

这篇关于如何查看用户在测验中的选择是否正确?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！

本站部分内容来源互联网,如果有图片或者内容侵犯了您的权益，请联系我们，我们会在确认后第一时间进行删除！

如何查看用户在测验中的选择是否正确?

问题描述

推荐答案

相关文档推荐