问题描述
我想include() 一个位于我的服务器上的 php 文件，带有额外的 GET 属性.但它不起作用:
I want to include() a php file located on my server, with additional GET attributes.
But it won't work:
include('search.php?q=1');
它给出的错误:
PHP Warning: include(): Failed opening './search.php?q=1' for inclusion
似乎它试图打开一个字面名为search.php?q=1"的文件，而不是打开search.php"文件并向其发送 GET 属性.
Seems like it tries to open a file literally named 'search.php?q=1' instead of opening the 'search.php' file and sending it the GET attributes.
*请注意，如果我不放置任何 GET 属性，它确实有效:
*Note that it does work if I don't put any GET attributes:
include('search.php');
推荐答案
您不想这样做:您必须执行 http 请求才能传递 GET 参数.您以这种方式调用的 PHP 脚本将在单独的 PHP 进程中运行.
You don't want to do this: You'd have to do a http request to be able to pass GET parameters. A PHP script you call in this way will run in a separate PHP process.
最佳方式是在本地包含文件:
The optimal way is to include the file locally:
include('search.php');
并手动将任何参数传递给它，例如
and to pass any parameters to it manually, like e.g.
$q = "1";
include('search.php'); // expects `$q` parameter
或者，更简洁地，将 search.php 中的任何内容放入可以使用参数调用的函数或类中:
or, more cleanly, putting whatever you have in search.php into a function or class that you can call with a parameter:
include('search.php'); // defines function my_search($q)
my_search(1);
这篇关于PHP include() 带有 GET 属性(包含 file.php?q=1)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！