本文介绍了如何从 PHP 数组为下拉选择字段创建嵌套列表?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
我的问题与本主题中描述的问题非常相似 从PHP数组为下拉选择字段创建嵌套列表 问题是,如果投资不连续,则错误地添加了破折号
My problem is very similar to the one described here in this topic Create nested list from PHP array for dropdown select field The problem is that if investments are not consecutive, then incorrectly adds a dash
function buildTree(Array $data, $parent = 0) {
$tree = array();
foreach ($data as $d) {
if ($d['parent'] == $parent) {
$children = buildTree($data, $d['id']);
// set a trivial key
if (!empty($children)) {
$d['_children'] = $children;
}
$tree[] = $d;
}
}
return $tree;
}
function printTree($tree, $r = 0, $p = null) {
foreach ($tree as $i => $t) {
$dash = ($t['parent'] == 0) ? '' : str_repeat('-', $r) .' ';
printf(" <option value='%d'>%s%s</option>
", $t['id'], $dash, $t['name']);
if ($t['parent'] == $p) {
// reset $r
$r = 0;
}
if (isset($t['_children'])) {
printTree($t['_children'], ++$r, $t['parent']);
}
}
}
此解决方案适用于这样的结构数组
This solution works for such a structure array
$rows = array(
array ('id' => 1, 'name' => 'Test 1', 'parent' => 0),
array ('id' => 2, 'name' => 'Test 1.1', 'parent' => 1),
array ('id' => 3, 'name' => 'Test 1.2', 'parent' => 1),
array ('id' => 4, 'name' => 'Test 1.2.1', 'parent' => 3),
array ('id' => 5, 'name' => 'Test 1.2.2', 'parent' => 3),
array ('id' => 6, 'name' => 'Test 1.2.2.1', 'parent' => 5),
array ('id' => 7, 'name' => 'Test 2', 'parent' => 0),
array ('id' => 8, 'name' => 'Test 2.1', 'parent' => 7),
);
但不适用于此
$rows = array(
array ('id' => 1, 'name' => 'Test 1', 'parent' => 0),
array ('id' => 2, 'name' => 'Test 1.1', 'parent' => 1),
array ('id' => 3, 'name' => 'Test 1.2', 'parent' => 1),
array ('id' => 4, 'name' => 'Test 1.2.1', 'parent' => 3),
array ('id' => 5, 'name' => 'Test 1.2.2', 'parent' => 3),
array ('id' => 6, 'name' => 'Test 1.2.2.1', 'parent' => 5),
array ('id' => 7, 'name' => 'Test 2', 'parent' => 0),
array ('id' => 8, 'name' => 'Test 2.1', 'parent' => 1),
array ('id' => 9, 'name' => 'another data', 'parent' => 1),
);
我怎样才能改变它?对不起我的英语
How can I change it? sorry for my english
推荐答案
它不起作用,因为您没有正确设置父"属性.即使名称是Test 2.1",使用此算法,您也必须设置父索引.如果您将数组更改为此,它将起作用:
It does not work because you are not setting the "parent" attribute right. Even if the name is "Test 2.1", using this algorithm, you have to set the parent index. If you change your array to this, it'll work:
$rows = array(
array ('id' => 1, 'name' => 'Test 1', 'parent' => 0),
array ('id' => 2, 'name' => 'Test 1.1', 'parent' => 1),
array ('id' => 3, 'name' => 'Test 1.2', 'parent' => 1),
array ('id' => 4, 'name' => 'Test 1.2.1', 'parent' => 3),
array ('id' => 5, 'name' => 'Test 1.2.2', 'parent' => 3),
array ('id' => 6, 'name' => 'Test 1.2.2.1', 'parent' => 5),
array ('id' => 7, 'name' => 'Test 2', 'parent' => 0),
array ('id' => 8, 'name' => 'Test 2.1', 'parent' => 7),
array ('id' => 9, 'name' => 'another data with no parent', 'parent' => 0),
);
这篇关于如何从 PHP 数组为下拉选择字段创建嵌套列表?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!
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