PHP:显示目录中的最新图像?

问题描述

我有一个摄像头服务器将图像通过 FTP 传输到网络服务器.任何人都可以建议我需要的 PHP 代码片段来查看服务器的公共根目录 (/public_html) 并显示最近的四个图像吗?

I have a camera server FTPing images to a webserver. Can anyone suggest the PHP snippet I'd need that would look through the server's public root directory (/public_html) and display the four most recent images?

我可以告诉相机服务器按日期/时间命名上传的图像，但需要[例如.image-021020102355.jpg 用于 2010 年 10 月 2 日晚上 11:55 创建的图像]

I can tell the camera server to name uploaded images by date/time, however needed [eg. image-021020102355.jpg for an image created 2nd oct 2010 at 11:55pm]

谢谢！

推荐答案

应该这样做:

<?php
foreach (glob('*.jpg') as $f) {
    # store the image name with the last modification time and imagename as a key
    $list[filemtime($f) . '-' . $f] = $f;
}   

$keys = array_keys($list);      
sort($keys);                    # sort is oldest to newest,

echo $list[array_pop($keys)];   # Newest
echo $list[array_pop($keys)];   # 2nd newest

如果您可以使文件名 YYYYMMDDHHMM.jpg sort() 可以将它们按正确的顺序排列，这将起作用:

If you can make the filenames YYYYMMDDHHMM.jpg sort() can put them in the right order and this would work:

<?php 
foreach (glob('*.jpg') as $f) {
    # store the image name
    $list[] = $f;
}

sort($list);                    # sort is oldest to newest,

echo array_pop($list);   # Newest
echo array_pop($list);   # 2nd newest

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