问题描述

我需要从重复的值中获取键.我尝试使用 array_search 并且效果很好，但是我只得到了第一个值作为命中.

I need to get the keys from values that are duplicates. I tried to use array_search and that worked fine, BUT I only got the first value as a hit.

我需要从重复值中获取两个键，在本例中为 0 和 2.作为数组输出的搜索结果会很好.

I need to get both keys from the duplicate values, in this case 0 and 2. The search result output as an array would be good.

是否有一个 PHP 函数可以做到这一点，还是我需要编写一些多个循环来做到这一点?

Is there a PHP function to do this or do I need to write some multiple loops to do it?

$list[0][0] = "2009-09-09";
$list[0][1] = "2009-05-05";
$list[0][2] = "2009-09-09";
$list[1][0] = "first-paid";
$list[1][1] = "1";
$list[1][2] = "last-unpaid";

echo array_search("2009-09-09",$list[0]);

推荐答案

你想要 array_keys 与搜索值

array_keys($list[0], "2009-09-09");

这将返回具有指定值的键数组，在您的情况下为 [0, 2].如果你也想找到重复的，你可以先通过 array_unique，然后在原始数组上使用 array_keys 迭代该数组；返回长度大于 1 的数组的任何内容都是重复的，结果是存储重复项的键.比如……

which will return an array of the keys with the specified value, in your case [0, 2]. If you want to find the duplicates as well, you can first make a pass with array_unique, then iterate over that array using array_keys on the original; anything which returns an array of length > 1 is a duplicate, and the result is the keys in which the duplicates are stored. Something like...

$uniqueKeys = array_unique($list[0])

foreach ($uniqueKeys as $uniqueKey)
{
  $v = array_keys($list[0], $uniqueKey);

  if (count($v) > 1)
  {
    foreach ($v as $key)
    {
      // Work with $list[0][$key]
    }

  }
}

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