问题描述
我有一个 PHP 论坛，它的日期类似于表单dd/mm/yyyy hh:mm:ss.但是，我需要以 yyyy-mm-dd hh:mm:ss 的格式将其作为 DATETIME 插入到 SQL 中.如何转换这些数据?
I have a forum in PHP which takes a date like in the form
dd/mm/yyyy hh:mm:ss. However, I need to insert it for SQL as a DATETIME in the format as yyyy-mm-dd hh:mm:ss. How can I convert this data?
推荐答案
你的日期时间格式错误:dd/mm/yyyy hh:mm:ss.可能你的意思是 d/m/Y H:i:s
Your date time format is wrong: dd/mm/yyyy hh:mm:ss. Probably you mean d/m/Y H:i:s
如果您有 5.3+ 版本，则可以安全地将日期时间转换为另一种格式.这是一个例子:
If you have 5.3+ version there is safe way to convert the date time into another format. Here's an example:
$timestamp = '31/05/2001 12:22:56';
$timestamp = DateTime::createFromFormat('d/m/Y H:i:s', $timestamp);
echo $timestamp->format('Y-m-d H:i:s');
或者如果你喜欢更程序化的方式:
or if you like more procedural way:
$timestamp = '31/05/2001 12:22:56';
$timestamp = date_create_from_format('d/m/Y H:i:s', $timestamp);
echo date_format($timestamp, 'Y-m-d H:i:s');
注意以前的建议.有些是完全错误的，有些可能会导致错误.
Be careful with previous suggestions. Some are completely wrong and others could lead to errors.
这篇关于在 SQL 中使用 PHP 为 DATETIME 转换日期的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！