问题描述
我的理解是，由于 PHP 使用毫秒表示日期的性质，您不能表示 2038 年之后的日期.我有一个问题，我想计算远在未来的日期.几千年后.
I am of of the understanding that due to the nature that PHP represents dates using milliseconds, you cannot represent dates past 2038. I have a problem where I want to calculate dates far in the future. Thousands of years away.
显然，由于限制，我不能使用 php date 函数来表示这个日期，但是，我有一些东西在我身边......我想要做的就是存储年、月和日.我不关心小时、分钟、秒和毫秒.
Obviously I cannot use the php date function to represent this date because of the limit, however, I have something on my side... All I want to do is store the year, month and day. I do not care for the hour, minute, seconds and milliseconds.
我是否正确地认为，如果不包括这些额外信息，我应该能够对未来进行更远的计算，因为我愿意丢弃大量信息.这是当前执行此操作的任何库吗?如果没有，有没有人对如何解决这个问题有任何建议?
Am I correct in thinking that without including this additional information I should be able to calculate a lot further into the future because I am willing to discard a lot of information. Is this any library that currently does this? If not does any have any advice on how to approach this problem?
推荐答案
您也可以使用 DateTime 类，它在内部独立地表示时间分量.因此它不受 2038 限制的影响(除非您使用 ::getTimestamp).
You can alternatively use the DateTime class, which internally represents the time components independently. Thus it is not susceptible to the 2038 limitation (unless you use ::getTimestamp).
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