如何将列表转换为 Python 中的嵌套字典

How to turn a list into nested dict in Python(如何将列表转换为 Python 中的嵌套字典)

问题描述

需要转x:

X = [['A', 'B', 'C'], ['A', 'B', 'D']]

进入 Y:

Y = {'A': {'B': {'C','D'}}}

更具体地说，我需要从绝对路径列表中创建一个文件夹和文件树，如下所示:

More specifically, I need to create a tree of folders and files from a list of absolute paths, which looks like this:

paths = ['xyz/123/file.txt', 'abc/456/otherfile.txt']

其中，每个路径都是split("/")，如伪示例中的['A', 'B', 'C'].

where, each path is split("/"), as per ['A', 'B', 'C'] in the pseudo example.

由于这代表文件和文件夹，显然，在同一级别(数组的索引)上，相同的名称字符串不能重复.

As this represents files and folders, obviously, on the same level (index of the array) same name strings can't repeat.

推荐答案

X = [['A', 'B', 'C'], ['A', 'B', 'D'],['W','X'],['W','Y','Z']]
d = {}

for path in X:
    current_level = d
    for part in path:
        if part not in current_level:
            current_level[part] = {}
        current_level = current_level[part]

这给我们留下了包含 {'A': {'B': {'C': {}, 'D': {}}}, 'W': {'Y': {'Z':{}}，'X':{}}}.任何包含空字典的项目要么是文件，要么是空目录.

This leaves us with d containing {'A': {'B': {'C': {}, 'D': {}}}, 'W': {'Y': {'Z': {}}, 'X': {}}}. Any item containing an empty dictionary is either a file or an empty directory.

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