多处理进程中的共享状态

Shared state in multiprocessing Processes(多处理进程中的共享状态)

问题描述

请考虑以下代码:

import time
from multiprocessing import Process

class Host(object):
    def __init__(self):
        self.id = None
    def callback(self):
        print "self.id = %s" % self.id
    def bind(self, event_source):
        event_source.callback = self.callback

class Event(object):
    def __init__(self):
        self.callback = None
    def trigger(self):
        self.callback()

h = Host()
h.id = "A"
e = Event()
h.bind(e)
e.trigger()

def delayed_trigger(f, delay):
    time.sleep(delay)
    f()

p = Process(target = delayed_trigger, args = (e.trigger, 3,))
p.start()

h.id = "B"
e.trigger()

这给出了输出

self.id = A
self.id = B
self.id = A

但是，我希望它能给

self.id = A
self.id = B
self.id = B

..因为在调用触发方法时，h.id 已经更改为B".

..because the h.id was already changed to "B" by the time the trigger method was called.

似乎在启动单独进程的那一刻创建了主机实例的副本，因此原始主机中的更改不会影响该副本.

It seems that a copy of host instance is created at the moment when the separate Process is started, so the changes in the original host do not influence that copy.

在我的项目中(当然更详细)，主机实例字段会不时更改，重要的是由在单独进程中运行的代码触发的事件能够访问这些更改.

In my project (more elaborate, of course), the host instance fields are altered time to time, and it is important that the events that are triggered by the code running in a separate process, have access to those changes.

推荐答案

多处理 在单独的进程中运行东西.在发送时不复制内容几乎是不可想象的，因为在进程之间共享内容需要共享内存或通信.

multiprocessing runs stuff in separate processes. It is almost inconceivable that things are not copied as they're sent, as sharing stuff between processes requires shared memory or communication.

事实上，如果您仔细阅读该模块，您可以通过 显式通信，或通过 显式共享对象(属于非常有限的语言子集，必须由 Manager).