Python:从 `datetime.datetime` 转换为 `time.time`

问题描述

在 Python 中，如何将 datetime.datetime 转换为从 time.time 函数获得的那种 float?

In Python, how do I convert a datetime.datetime into the kind of float that I would get from the time.time function?

推荐答案

使用时间元组方法不难，仍然保留微秒:

It's not hard to use the time tuple method and still retain the microseconds:

>>> t = datetime.datetime.now()
>>> t
datetime.datetime(2011, 11, 5, 11, 26, 15, 37496)

>>> time.mktime(t.timetuple()) + t.microsecond / 1E6
1320517575.037496

这篇关于Python:从 `datetime.datetime` 转换为 `time.time`的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！