问题描述

在 Python 中，我想转换一个字符串列表:

l = ['sam','1','dad','21']

并将整数转换为整数类型，如下所示:

t = ['sam',1,'dad',21]

我试过了:

t = [map(int, x) for x in l]

但显示错误.

如何将列表中的所有 intable 字符串转换为 int，而将其他元素保留为字符串?

我的列表可能是多维的.一种适用于通用列表的方法会更好:

l=[['aa','2'],['bb','3']]

我会使用自定义函数:

def try_int(x):尝试:返回整数(x)除了ValueError:返回 x

例子:

>>>[try_int(x) for x in ['sam', '1', 'dad', '21']]['山姆'，1，'爸爸'，21]

<小时>

如果您需要将上述内容应用于列表列表，为什么在构建嵌套列表时不将这些字符串转换为 int?p>

无论如何，如果需要，只是选择如何遍历这样的嵌套列表并应用上述方法.

这样做的一种方法可能是:

>>>list_of_lists = [['aa', '2'], ['bb', '3']]>>>[[try_int(x) for x in lst] for lst in list_of_lists][['aa', 2], ['bb', 3]]

您显然可以将其重新分配给 list_of_lists:

>>>list_of_lists = [[try_int(x) for x in lst] for lst in list_of_lists]

In Python, I want to convert a list of strings:

l = ['sam','1','dad','21']

and convert the integers to integer types like this:

t = ['sam',1,'dad',21]

I tried:

t = [map(int, x) for x in l]

but is showing an error.

How could I convert all intable strings in a list to int, leaving other elements as strings?

My list might be multi-dimensional. A method which works for a generic list would be preferable:

l=[['aa','2'],['bb','3']]

I'd use a custom function:

def try_int(x):
    try:
        return int(x)
    except ValueError:
        return x

Example:

>>> [try_int(x) for x in  ['sam', '1', 'dad', '21']]
['sam', 1, 'dad', 21]

Edit: If you need to apply the above to a list of lists, why didn't you converted those strings to int while building the nested list?

Anyway, if you need to, it's just a matter of choice on how to iterate over such nested list and apply the method above.

One way for doing that, might be:

>>> list_of_lists = [['aa', '2'], ['bb', '3']]
>>> [[try_int(x) for x in lst] for lst in list_of_lists]
[['aa', 2], ['bb', 3]]

You can obviusly reassign that to list_of_lists:

>>> list_of_lists = [[try_int(x) for x in lst] for lst in list_of_lists]

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