如何从 0000 循环到 9999 并将数字转换为相对字符串?

问题描述

我想得到一些字符串，范围从0000到9999，也就是说，我想打印以下字符串:

i want to get some string, range from 0000 to 9999, that's to say, i want to print the following string:

0000
0001
0002
0003
0004
0005
0006
....
9999

我尝试使用 print " ".join([str(num) for num in range(0, 9999)])，但失败了，我得到以下数字:

i tried to use print " ".join([str(num) for num in range(0, 9999)]), but failed, i get the following number:

0
1
2
3
4
5
6
...
9999

我希望python自动添加前缀0，使数字保持4位数字时间.谁能帮帮我?任何帮助表示赞赏.

i want python to add the prefix 0 automatically, making the number remain 4 bit digits all the time. can anyone give a hand to me? any help appreciated.

推荐答案

获得所需内容的一种方法是使用字符串格式:

One way to get what you want is to use string formatting:

>>> for i in range(10):
...     '{0:04}'.format(i)
... 
'0000'
'0001'
'0002'
'0003'
'0004'
'0005'
'0006'
'0007'
'0008'
'0009'

所以要做你想做的，这样做:

So to do what you want, do this:

print("
".join(['{0:04}'.format(num) for num in range(0, 10000)]))

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