Python子进程将孩子的输出输出到文件和终端?

问题描述

I'm running a script that executes a number of executables by using

subprocess.call(cmdArgs,stdout=outf, stderr=errf)

when outf/errf is either None or a file descriptor (different files for stdout/stderr).

Is there any way I can execute each exe so that the stdout and stderr will be written to the files and terminal together?

The call() function is just Popen(*args, **kwargs).wait(). You could call Popen directly and use stdout=PIPE argument to read from p.stdout:

#!/usr/bin/env python
import sys
from subprocess import Popen, PIPE
from threading import Thread


def tee(infile, *files):
    """Print `infile` to `files` in a separate thread."""

    def fanout(infile, *files):
        with infile:
            for line in iter(infile.readline, b""):
                for f in files:
                    f.write(line)

    t = Thread(target=fanout, args=(infile,) + files)
    t.daemon = True
    t.start()
    return t


def teed_call(cmd_args, **kwargs):
    stdout, stderr = [kwargs.pop(s, None) for s in ["stdout", "stderr"]]
    p = Popen(
        cmd_args,
        stdout=PIPE if stdout is not None else None,
        stderr=PIPE if stderr is not None else None,
        **kwargs
    )
    threads = []
    if stdout is not None:
        threads.append(
            tee(p.stdout, stdout, getattr(sys.stdout, "buffer", sys.stdout))
        )
    if stderr is not None:
        threads.append(
            tee(p.stderr, stderr, getattr(sys.stderr, "buffer", sys.stderr))
        )
    for t in threads:
        t.join()  # wait for IO completion
    return p.wait()


outf, errf = open("out.txt", "wb"), open("err.txt", "wb")
assert not teed_call(["cat", __file__], stdout=None, stderr=errf)
assert not teed_call(["echo", "abc"], stdout=outf, stderr=errf, bufsize=0)
assert teed_call(["gcc", "a b"], close_fds=True, stdout=outf, stderr=errf)

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