1. <legend id='UQ8D2'><style id='UQ8D2'><dir id='UQ8D2'><q id='UQ8D2'></q></dir></style></legend>
    1. <tfoot id='UQ8D2'></tfoot>

      <small id='UQ8D2'></small><noframes id='UQ8D2'>

        <bdo id='UQ8D2'></bdo><ul id='UQ8D2'></ul>
      <i id='UQ8D2'><tr id='UQ8D2'><dt id='UQ8D2'><q id='UQ8D2'><span id='UQ8D2'><b id='UQ8D2'><form id='UQ8D2'><ins id='UQ8D2'></ins><ul id='UQ8D2'></ul><sub id='UQ8D2'></sub></form><legend id='UQ8D2'></legend><bdo id='UQ8D2'><pre id='UQ8D2'><center id='UQ8D2'></center></pre></bdo></b><th id='UQ8D2'></th></span></q></dt></tr></i><div id='UQ8D2'><tfoot id='UQ8D2'></tfoot><dl id='UQ8D2'><fieldset id='UQ8D2'></fieldset></dl></div>

      从字典值中创建一个集合

      Making a set from dictionary values(从字典值中创建一个集合)

        <legend id='iSEXg'><style id='iSEXg'><dir id='iSEXg'><q id='iSEXg'></q></dir></style></legend>

        • <bdo id='iSEXg'></bdo><ul id='iSEXg'></ul>
          <i id='iSEXg'><tr id='iSEXg'><dt id='iSEXg'><q id='iSEXg'><span id='iSEXg'><b id='iSEXg'><form id='iSEXg'><ins id='iSEXg'></ins><ul id='iSEXg'></ul><sub id='iSEXg'></sub></form><legend id='iSEXg'></legend><bdo id='iSEXg'><pre id='iSEXg'><center id='iSEXg'></center></pre></bdo></b><th id='iSEXg'></th></span></q></dt></tr></i><div id='iSEXg'><tfoot id='iSEXg'></tfoot><dl id='iSEXg'><fieldset id='iSEXg'></fieldset></dl></div>

            <tbody id='iSEXg'></tbody>
          • <small id='iSEXg'></small><noframes id='iSEXg'>

            <tfoot id='iSEXg'></tfoot>

                本文介绍了从字典值中创建一个集合的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                问题描述

                I want to create a set from the values of an existing dict

                def function(dictionary):
                    ... 
                    return set_of_values
                

                Say my dictionary looks like this: {'1': 'Monday', '2': 'Tuesday', '3': 'Monday'}

                I want a set returned that only contains the unique values, like this:

                {'Monday', 'Tuesday'}
                

                解决方案

                For Python:

                set(d.values())
                

                Equivalent on Python 2.7:

                set(d.viewvalues())
                

                If you need a cross-compatible Python 2.7/3.x code:

                {d[k] for k in d}
                

                这篇关于从字典值中创建一个集合的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

                本站部分内容来源互联网,如果有图片或者内容侵犯了您的权益,请联系我们,我们会在确认后第一时间进行删除!

                相关文档推荐

                groupby multiple coords along a single dimension in xarray(在xarray中按单个维度的多个坐标分组)
                Group by and Sum in Pandas without losing columns(Pandas中的GROUP BY AND SUM不丢失列)
                Group by + New Column + Grab value former row based on conditionals(GROUP BY+新列+基于条件的前一行抓取值)
                Groupby and interpolate in Pandas(PANDA中的Groupby算法和插值算法)
                Pandas - Group Rows based on a column and replace NaN with non-null values(PANAS-基于列对行进行分组,并将NaN替换为非空值)
                Grouping pandas DataFrame by 10 minute intervals(按10分钟间隔对 pandas 数据帧进行分组)

                <small id='EGTxt'></small><noframes id='EGTxt'>

                <tfoot id='EGTxt'></tfoot>

                      <tbody id='EGTxt'></tbody>
                    <i id='EGTxt'><tr id='EGTxt'><dt id='EGTxt'><q id='EGTxt'><span id='EGTxt'><b id='EGTxt'><form id='EGTxt'><ins id='EGTxt'></ins><ul id='EGTxt'></ul><sub id='EGTxt'></sub></form><legend id='EGTxt'></legend><bdo id='EGTxt'><pre id='EGTxt'><center id='EGTxt'></center></pre></bdo></b><th id='EGTxt'></th></span></q></dt></tr></i><div id='EGTxt'><tfoot id='EGTxt'></tfoot><dl id='EGTxt'><fieldset id='EGTxt'></fieldset></dl></div>

                      • <bdo id='EGTxt'></bdo><ul id='EGTxt'></ul>
                        <legend id='EGTxt'><style id='EGTxt'><dir id='EGTxt'><q id='EGTxt'></q></dir></style></legend>