为什么'True == not False'是Python中的语法错误?

Why is this a syntax error? I would expect not False to be an expression that returns a boolean value, and True == <x> to be valid syntax wherever <x> is an expression with valid syntax.

推荐答案

和Python 中的运算符优先级(解释器认为您在比较 True 和 not，因为 == 的优先级高于 not).您需要一些括号来阐明操作顺序:

It has to do with operator precedence in Python (the interpreter thinks you're comparing True to not, since == has a higher precedence than not). You need some parentheses to clarify the order of operations:

True == (not False)

一般情况下，您不能在没有括号的比较右侧使用 not.但是，我想不出你需要在比较右侧使用 not 的情况.

In general, you can't use not on the right side of a comparison without parentheses. However, I can't think of a situation in which you'd ever need to use a not on the right side of a comparison.

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