如何从 Django 中的 inlineadmin 获取当前模型实例

问题描述

我正在使用 formfield_for_manytomany.formfield_for_foreignkey" rel="noreferrer">django 文档.但在该函数中，我需要获取当前正在编辑的父对象.

I am using the formfield_for_manytomany given in django documentation. But inside that function I need to get the current parent object being edited.

def formfield_for_manytomany(self, db_field, request, **kwargs):
    if db_field.name == "car":
        kwargs["queryset"] = Cars.objects.filter(owner=person)
    return super(myModel, self).formfield_for_manytomany(db_field, request, **kwargs)

如何获取正在编辑的人?

How can I get the person being edited?

推荐答案

如果 person 无法从 request 轻松获取，则可能需要通过覆盖手动传递ModelAdmin.get_form() 或 InlineModelAdmin.get_formset():

If the person cannot be easily got from request, you may need to manually pass it by overriding ModelAdmin.get_form() or InlineModelAdmin.get_formset():

from functools import partial

class MyModelAdmin(admin.ModelAdmin):
    def get_form(self, request, obj=None, **kwargs):
        kwargs['formfield_callback'] = partial(self.formfield_for_dbfield, request=request, obj=obj)
        return super(MyModelAdmin, self).get_form(request, obj, **kwargs)

    def formfield_for_dbfield(self, db_field, **kwargs):
        person = kwargs.pop('obj', None)
        formfield = super(MyModelAdmin, self).formfield_for_dbfield(db_field, **kwargs)
        if db_field.name == "car" and person:
            formfield.queryset = Cars.objects.filter(owner=person)
        return formfield 

# or its inline
class MyInlineModelAdmin(admin.StackedInline):
    def get_formset(self, request, obj=None, **kwargs):
        kwargs['formfield_callback'] = partial(self.formfield_for_dbfield, request=request, obj=obj)
        return super(MyInlineModelAdmin, self).get_formset(request, obj, **kwargs)

    def formfield_for_dbfield(self, db_field, **kwargs):
        person = kwargs.pop('obj', None)
        formfield = super(MyInlineModelAdmin, self).formfield_for_dbfield(db_field, **kwargs)
        if db_field.name == "car" and person:
            formfield.queryset = Cars.objects.filter(owner=person)
        return formfield 

或者

class MyModelAdmin(admin.ModelAdmin):
    def get_form(self, request, obj=None, **kwargs):
        kwargs['formfield_callback'] = partial(self.formfield_for_dbfield, request=request, obj=obj)
        return super(MyModelAdmin, self).get_form(request, obj, **kwargs)

    def formfield_for_dbfield(self, db_field, **kwargs):
        if db_field.name != "car":
            kwargs.pop('obj', None)
        return super(MyModelAdmin, self).formfield_for_dbfield(db_field, **kwargs)

    def formfield_for_manytomany(self, db_field, request=None, **kwargs):
        person = kwargs.pop('obj', None)
        if db_field.name == "car" and person:
            kwargs['queryset'] = Cars.objects.filter(owner=person)
        return super(MyModelAdmin, self).formfield_for_manytomany(db_field, request, **kwargs)

这篇关于如何从 Django 中的 inlineadmin 获取当前模型实例的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！