问题描述
我有九组配色方案，我想将它们应用于一系列 div.使用 :nth-child(1), :nth-child(2)... 适用于前九个，但我希望之后重复该序列，但我不能围绕 (3n+2) 表示法缠绕我的头......我想我明白了，但我似乎无法哄它做我想做的事.
I have nine sets of color schemes that I want to apply to a sequence of divs. Using :nth-child(1), :nth-child(2)... works for the first nine, but I'd like the sequence to then repeat after that, and I can't wrap my head around the (3n+2) notation... I think I get it, but I can't seem to coax it into doing what I want.
这可能吗，还是我应该在写出每个 div 时只为它们应用一个类?
Is this possible, or should I just apply a class to each div as I write them out?
推荐答案
如果你的意思是你需要对每九个连续的元素应用不同的规则，你必须使用这九个选择器:
If you mean you need to apply different rules to every nine consecutive elements, you have to use these nine selectors:
:nth-child(9n+1)
:nth-child(9n+2)
:nth-child(9n+3)
:nth-child(9n+4)
:nth-child(9n+5)
:nth-child(9n+6)
:nth-child(9n+7)
:nth-child(9n+8)
:nth-child(9n+9) /* Or :nth-child(9n) */
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