MongoDB计算不同的价值?

MongoDB count distinct value?(MongoDB计算不同的价值?)

问题描述

下面显示我的代码.我必须计算重复的不同值的次数.在这里，我在结果"中存储了不同的值.我使用 collection.count() 来计算，但它不起作用.请任何人告诉我我必须在哪里出错.非常感谢.

Here below show my code. I have to calculate the how many times distinct value repeated. Here i have store distinct value in "results".I used collection.count() to calculate but it's not work. please any one tell me where i have to mistake. Thank you very much .

var DistinctIntoSingleDB = function(Collection,arr,opt,distVal,callback){
 Collection.find({}).distinct(distVal, function(err, results) {
      if(!err && results){
            console.log("Distinct Row Length :", results.length);
            var a,arr1 = [];
            for(var j=0; j<results.length; j++){
                collection.count({'V6': results[j]}, function(err, count) {
                      console.log(count)
                });

                arr1.push(results[j]+ " : " +a);
            }
            callback(results,arr1);
      }else{
           console.log(err, results);
           callback(results);
      }
 });

推荐答案

在集合 'col1' 上获取字段 'field1' 的不同值并写入单独的集合 'distinctCount'.如果集合很大，也允许使用磁盘空间.

To get occurrences of distinct values of a field 'field1' on a collection 'col1' and write to a separate collection 'distinctCount'. Also allow to use disk space in case the collection is huge.

db.col1.aggregate(
          [{$group: {
              _id: "$field1",
              count: { $sum : 1 }
            }}, {
            $group: {
              _id: "$_id",
              count: { $sum : "$count" }
            }},{
              $out: "distinctCount"
            }],
         {allowDiskUse:true}
)

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