How can I get count of the Documents and filter them in efficient way? (mongoose)(我怎样才能获得文档的数量并以有效的方式过滤它们?(猫鼬))
问题描述
I'm implementing search function that is simply find document in mongoDB. I want to .skip(x) and .limit(x) on result to simulate paging result, but can I get total count of document (before skip and limit) and get filtered result at once?
Code that produce Expected Output :
db.Datas.find({ type: "Unknown" })
.then((result) => {
let count = result.length;
db.Datas.find({ type: "Unknown" })
.sort({ createdAt: -1 })
.skip((req.query.page - 1) * 10)
.limit(10)
.then((res) => {
res.json({ count: count, result: res });
});
})
.catch((err) => {});
But querying twice it somehow annoying, and it might be slow at large database.
I tried something like find({}).then(x => { ... }).sort(...) ... but isn't working because it only returns Promise.
How can I do this things in efficient way? or is just getting whole documents and skip, limit with JS-way (using .splice, or etc..) will be faster and efficient?
You can use $facet aggregation to achieve this.
db.Datas.aggregate([
{
$match: {
"type": "Unknown"
}
},
{
$sort: {
createdAt: -1
}
},
{
$facet: {
totalRecords: [
{
$count: "total"
}
],
data: [
{
$skip: 0
},
{
$limit: 5
}
]
}
}
])
Playground
Let's say you have these documents:
db={
"Datas": [
{
"_id": "5e390fc33285e463a0799689",
"type": "Known",
"createdAt": "2020-02-04T06:31:31.311Z",
"__v": 0
},
{
"_id": "5e390fd03285e463a079968a",
"type": "Known",
"createdAt": "2020-02-04T06:31:44.190Z",
"__v": 0
},
{
"_id": "5e390fda3285e463a079968b",
"type": "Unknown",
"createdAt": "2020-02-04T06:31:54.248Z",
"__v": 0
},
{
"_id": "5e390fdf3285e463a079968c",
"type": "Unknown",
"createdAt": "2020-02-04T06:31:59.993Z",
"__v": 0
},
{
"_id": "5e390fec3285e463a079968d",
"type": "Unknown",
"createdAt": "2020-02-04T06:32:12.336Z",
"__v": 0
},
{
"_id": "5e390ffd3285e463a079968e",
"type": "Unknown",
"createdAt": "2020-02-04T06:32:29.670Z",
"__v": 0
},
{
"_id": "5e3910163285e463a079968f",
"type": "Unknown",
"createdAt": "2020-02-04T06:32:54.131Z",
"__v": 0
},
{
"_id": "5e3910213285e463a0799690",
"type": "Unknown",
"createdAt": "2020-02-04T06:33:05.166Z",
"__v": 0
}
]
}
Response will be like this:
[
{
"data": [
{
"__v": 0,
"_id": "5e3910213285e463a0799690",
"createdAt": "2020-02-04T06:33:05.166Z",
"type": "Unknown"
},
{
"__v": 0,
"_id": "5e3910163285e463a079968f",
"createdAt": "2020-02-04T06:32:54.131Z",
"type": "Unknown"
},
{
"__v": 0,
"_id": "5e390ffd3285e463a079968e",
"createdAt": "2020-02-04T06:32:29.670Z",
"type": "Unknown"
},
{
"__v": 0,
"_id": "5e390fec3285e463a079968d",
"createdAt": "2020-02-04T06:32:12.336Z",
"type": "Unknown"
},
{
"__v": 0,
"_id": "5e390fdf3285e463a079968c",
"createdAt": "2020-02-04T06:31:59.993Z",
"type": "Unknown"
}
],
"totalRecords": [
{
"total": 6
}
]
}
]
As you see, we got the total records with the filtered, sorted, skipped and limited data.
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本文标题为:我怎样才能获得文档的数量并以有效的方式过滤它们?(猫鼬)
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