从 jQuery.get 嵌套函数中获取 var

Get var out of jQuery.get nested function(从 jQuery.get 嵌套函数中获取 var)

问题描述

  function getUserHours(tyPe, tarGet){
    $.get('/activities/search', { 'type': tyPe }, 
    function(data){   
     var hourResultData = jQuery.parseJSON(data);
     var registeredHours = 0; 
     for (var i in hourResultData.activities){
      registeredHours += parseFloat(hourResultData.activities[i].hours);
     }
     $(tarGet).empty().append(registeredHours);
     return registeredHours;
   });

  }

我想要:

alert( getUserHours('r', '#reg-hours'));

提醒已注册的时间

推荐答案

只有关闭 AJAX 的异步 GET 才能直接返回数据:

Returning data directly will only work if you turn the asynchronous GET for AJAX off:

$.ajax({
    type: 'GET',
    url: '/activities/search',
    data: { 'type': tyPe },
    async : false,
    success : function() { }
 });

不建议这样做，因为浏览器会一直阻塞直到您的请求完成.相反，您应该继续遵循异步编程模型，使用函数回调:

This is not recommended, because the browser will block until you request is finished. Instead you should continue to follow the asynchronous programming model by using function callback:

$.ajax({
    type: 'GET',
    url: '/activities/search',
    data: { 'type': tyPe },
    async : false,
    success : function() { }
 });

function getUserHours(tyPe, tarGet, callback)
{
    $.get('/activities/search', { 'type': tyPe }, 
    function(data)
    {
        var hourResultData = jQuery.parseJSON(data);
        var registeredHours = 0; 
        for (var i in hourResultData.activities){
            registeredHours += parseFloat(hourResultData.activities[i].hours);
        }
        $(tarGet).empty().append(registeredHours);
        if($.isFunction(callback))
            callback(registeredHours);
    });
}

getUserHours('r', '#reg-hours', function(hours) {
    alert(hours);
});

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