Javascript“流行"从对象

问题描述

我编写了以下代码来从对象中弹出"一个属性，就好像它是一个数组一样.这看起来像是会让我被更严肃的程序员打的那种代码，所以我想知道这样做的正确方法是什么:

I wrote the following code to "pop" a property from an object as if it were an array. This looks like the kind of code that would get me slapped by more serious programmers, so I was wondering what is the proper way to do this:

// wrong way to pop:
for( key in profiles ){
    var profile = profiles[key];  // get first property
    profiles[key] = 0;            // Save over property just in case "delete" actually deletes the property contents instead of just removing it from the object
    delete profiles[key];         // remove the property from the object
    break;                        // "break" because this is a loop
}

我应该在上面提到，与真正的流行音乐"不同，我不需要对象以任何特定的顺序出现.我只需要取出一个并将其从其父对象中删除即可.

I should have mentioned above, that unlike a true "pop", I don't need the objects to come out in any particular order. I just need to get one out and remove it from its parent object.

推荐答案

for( key in profiles ){

你真的应该将 key 声明为 var.

You should really declare key as a var.

profiles[key] = 0;            // Save over property just in case "delete" actually deletes the property contents instead of just removing it from the object

是不必要的.删除不会触及属性的值(或者对于有setter但没有getter的属性，甚至要求它有一个值).

is unnecessary. Delete doesn't touch the value of the property (or in the case of a property that has a setter but no getter, even require that it have a value).

如果对象在其原型上有任何可枚举的属性，那么这会做一些奇怪的事情.考虑

If the object has any enumerable properties on its prototype, then this will do something odd. Consider

Object.prototype.foo = 42;

function take(obj) {
  for (var key in obj) {
    // Uncomment below to fix prototype problem.
    // if (!Object.hasOwnProperty.call(obj, key)) continue;
    var result = obj[key];
    // If the property can't be deleted fail with an error.
    if (!delete obj[key]) { throw new Error(); }
    return result;
  } 
}

var o = {};
alert(take(o));  // alerts 42
alert(take(o));  // still alerts 42

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