问题描述

我想做的事

describe('my object', function() {
  it('has these properties', function() {
    expect(Object.keys(myObject)).toEqual([
      'property1',
      'property2',
      ...
    ]);
  });
});

但当然 Object.keys 返回一个数组，根据定义，它是有序的......我更愿意让这个测试通过而不管属性排序(这对我来说很有意义，因为有无论如何都没有对象键排序的规范......(至少到 ES5)).

but of course Object.keys returns an array, which by definition is ordered...I'd prefer to have this test pass regardless of property ordering (which makes sense to me since there is no spec for object key ordering anyway...(at least up to ES5)).

我如何验证我的对象具有它应该具有的所有属性，同时确保它没有丢失任何属性，而不必担心以正确的顺序列出这些属性?

How can I verify my object has all the properties it is supposed to have, while also making sure it isn't missing any properties, without having to worry about listing those properties in the right order?

推荐答案

是 现在内置！

describe("jasmine.objectContaining", function() {
  var foo;

  beforeEach(function() {
    foo = {
      a: 1,
      b: 2,
      bar: "baz"
    };
  });

  it("matches objects with the expect key/value pairs", function() {
    expect(foo).toEqual(jasmine.objectContaining({
      bar: "baz"
    }));
    expect(foo).not.toEqual(jasmine.objectContaining({
      c: 37
    }));
  });
});

或者，您可以使用外部检查，如 _.has(包装 myObject.hasOwnProperty(道具)):

Alternatively, you could use external checks like _.has (which wraps myObject.hasOwnProperty(prop)):

var _ = require('underscore');
describe('my object', function() {
  it('has these properties', function() {
    var props = [
      'property1',
      'property2',
      ...
    ];
    props.forEach(function(prop){
      expect(_.has(myObject, prop)).toBeTruthy();
    })
  });
});

这篇关于Jasmine 测试对象属性的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！