如何获得按“值"降序排序的 map/reduce 结果?值?如果也使用列表函数可以实现吗?

我可以得到下面的结果集:

I can get the result set below:

{"rows":[
{"key":["111111",""],"value":7},
{"key":["111111","FFFF26"],"value":1},
{"key":["111111","FFFF44"],"value":7},
{"key":["111111","FFFF34"],"value":2}
]}

但是，我想让上面的结果集按值"值的降序排序.如果还使用列表功能可以实现吗?预期结果如下:

However, I want to get the result set above sorted within descending order of the "value" value. if also using list function can achieve that? the following would be expected results:

{"rows":[
{"key":["111111",""],"value":7},
{"key":["111111","FFFF44"],"value":7},
{"key":["111111","FFFF34"],"value":2},
{"key":["111111","FFFF26"],"value":1}
]}

推荐答案

如果要对结果集进行排序，则必须按值降序排序，可以使用比较器回调进行排序:

If you want to sort the result set you have to one that is sorted by value descending you can sort with a comparator callback:

// ES6 Syntax
let originalResult = {
"rows":[
  {"key":["111111",""],"value":7},
  {"key":["111111","FFFF26"],"value":1},
  {"key":["111111","FFFF44"],"value":7},
  {"key":["111111","FFFF34"],"value":2}
]}

let newResult = {
  rows: originalResult.rows.sort((a, b) => b.value - a.value)
} 

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