使用带有 Fetch API 响应的 Promise 仍然让我的数据返回未定义

问题描述

我正在构建一个简单的网络应用程序，允许用户在视频游戏中搜索玩家的统计数据.

I am building a simple web app that allows users to search the stats of a player in a video game.

这是我的代码

let player = [];
let proxy = "https://cors-anywhere.herokuapp.com/"
    let url =  proxy + "https://secure.runescape.com/m=hiscore_oldschool/index_lite.ws?player=Hess"

function getPlayer() {
  return fetch(url)
    .then((response) => response.text())
    .then((data) => console.log(data));
}
getPlayer().then((playerData) => {
  console.log(playerData);
  playerData.push(player);
  console.log(player);
});

如您所见，我正在尝试 console.log 响应并将响应推送到数组 player 以便以后可以在 player 中使用受感染的数据数组来执行一些其他操作.

As you can see, I am trying to console.log the response and push the response to an array player so I can later use the fecthed data in the player array to perform some other actions on.

为什么它返回未定义?为什么我的响应不会被推送到 player 数组中?

Why is it returning undefined? Why won't my response get pushed into the player array?

推荐答案

let player = [];
let proxy = "https://cors-anywhere.herokuapp.com/"
let url = proxy + "https://secure.runescape.com/m=hiscore_oldschool/index_lite.ws?player=Hess"

function getPlayer() {
    return fetch(url)
        .then((response) => response.text())
        .then((data) => {
            console.log(data)
            return data;
        });
}
getPlayer().then((playerData) => {
    console.log(playerData);
    player.push(playerData);
    console.log(player);
});

您需要确保在 .then() 的每一步都返回一个值.而你的 .push 是错误的方式

You need to make sure you are returning a value at each step of your .then(). And your .push is the wrong way round

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