合并两个编译步骤的 source maps

问题描述

我的 Web 应用程序有一个两步编译过程.首先，我将 CoffeeScript 文件编译成 JavaScript 文件 [1].然后 JavaScript 文件(来自 CoffeeScript 的文件和外部文件，如 grunt-angular-templates 从 AngularJS 模板生成的文件)由 Google Closure Compiler [2] 编译成单个最小化文件.

I've got a two-step compilation process for my web application. Firstly, I compile CoffeeScript files into JavaScript files [1]. Then the JavaScript files (both ones that come from CoffeeScript, and external ones, like produced from AngularJS templates by grunt-angular-templates) are compiled by Google Closure Compiler [2] into a single minimized file.

CoffeeScript ---[1]---> JavaScript --[2]--
                                           ->
AngularJS templates --> JavaScript ----------> single minimized JS file
                                           /->
                    other JS files -------/

步骤 [1] 和 [2] 都生成源映射.

Both steps [1] and [2] produce source maps.

是否可以将这些源映射组合成一个单一的源映射，这样我就可以从运行最小化 JS 文件的 Web 浏览器中调试 CoffeeScript 文件?

Is it possible to combine these source maps into a single source map that would allow me to debug CoffeeScript files from a web browser that runs the minimized JS file?

换句话说:假设源映射 [1] 由一个函数表示:

In other words: let say the source map [1] is represented by a function:

f(position in CoffeeScript) = position in JavaScript

源图[2]用一个函数表示:

and the source map [2] is represented by a function:

g(position in JavaScript) = position in minimized JS

我想得到一个由函数组合表示的源映射:

I'd like to get a source map which is represented by a function composition:

h(position in CoffeeScript) = g(f(position in CoffeeScript)) = 
                            = position in minimized JS

推荐答案

试试 巫术 - 就是正是为此目的而设计的(我是作者，我来这里是为了寻找相关工具的信息).只要 .map 文件位于正确的位置(或作为数据 URI 内联)，您只需在生成的文件上运行 sorcery ，它就会找到中间源映射和组合它们.

Try sorcery - it's designed for exactly this purpose (I'm the author, I came here looking for info on related tools). As long as the .map files are in the correct location (or inlined as data URIs), you just run sorcery on the generated file and it will locate the intermediate sourcemaps and compose them.

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